Lagrange-Interpolation für die Kostenfunktion
Author: Prof. Dr. Dörte Haftendorn
Date: Nov 08

K_f sind die Fixkosten.

Kostenfunktion, ziehe an den Punkten

Ha 08

Kosten

BO...

BM

Kv

B = (1.0064633260711693, 2.3354393609295574)
K_f = Point(yAxis)
C = (2.4938343458096557, 2.5753086419753077)
D = (3.895663911655199, 3.1023238925199705)
K = Polynomial({K_f, B, C, D})
Kgrenz(x) = K'(x)
Kv(x) = K(x) - y(K_f)
stueckkv(x) = Kv(x) / x
A = Intersect(stueckkv, Kgrenz, (3.2230759751818217, 0.3516116808235566))
stueckk(x) = K(x) / x
E = Extremum(Kgrenz)
G = Intersect(stueckk, Kgrenz, (3.894932392597065, 0.7963530077391174))
BO: (x(G), 0)
F = Intersect(stueckkv, Kgrenz, (x(A), 1.14897))
BM: (x(F), 0)
lPug = Segment(G, BO)
kPug = Segment(F, BM)
a = true
b = true
Kgrenz'(x) = Kgrenz'(x)
c = false
d = Segment(BM, BO)
e: stueckkv(0)