r

1/10 des Volumens wird dargestellt

Ortskurve

Ha 1996 / 2005/2014

Extremwertaufgabe
Wasserzylinder im Mühlendach

Ha 1996-2014

O = Intersect(xAxis, yAxis)
A = Point(xAxis)
M = Midpoint(A, O)
R_1 = Segment(M, O)
ga = OrthogonalLine(M, xAxis)
D = Point(ga)
P, d, a, b = Polygon(A, O, D)
Q = Point(R_1)
c = OrthogonalLine(Q, xAxis)
F = Intersect(c, a)
e = OrthogonalLine(F, c)
G = Intersect(b, e)
H_1 = Mirror(Q, M)
ZylQ, k, g, h, e_1 = Polygon(H_1, G, F, Q)
r = Segment(M, Q)
X: (r, 0)
V: ((3.141592653589793 * r^(2)) * h)
Vol: (r, V / 10)
i = Segment(Vol, X)
I = (-11.866666666666678, 8.533333333333363)
H = Segment(D, M)
x_2 = Segment(O, X)
OrtVol = Locus(Vol, Q)
ww = false
Text1: "h = " + h
R = Segment(M, A)
f(x) = ((((-H) * π) * x^(3)) + (((H * R) * π) * x^(2))) / ((10 * R))
f'(x) = f'(x)