(3 a^2-2b)^2

x=a

9 x^2-4 b^2

9 x^4-4b^2

9 x^4 - 6 x^2 b + 4 b^2

9x^4-12 b x^2+4 b^2

Löse auf

Variere dann b

Termumformungen testen

Ha 06

9 x^4-12 x^2+4 b^4

a = 1
b = 0.9999999999999999
f(x) = (3 x² - 2 b)²
g(x) = 9 x² - 4 b²
h(x) = 9 x⁴ - 6 x² b + 4 b²
f_1(x) = 9 x⁴ - 4 b²
g_1(x) = 9 x⁴ - 6 x² b + 4 b²
h_1(x) = 9 x⁴ - 12 b x² + 4 b²
f_2(x) = 9 x⁴ - 12 x² + 4 b⁴