Goldenes Rechteck
Author: Haftendorn
Date: Jan+dez 05

Ha 1/05

Die Viertelbögen ergeben die Goldene Schnecke.

Goldene Schnecke : Fortgesetzte Abspaltung eines

 Quadrates vom Goldenen Rechteck.

k falsch

alles fällt

auseinander

A = Intersect(xAxis, yAxis)
B = Point(yAxis)
k = 1.6336300000000894
C: (k y(B), y(B))
D: (k y(B), 0)
P, a, b, c, d = Polygon(A, B, C, D)
e = Circle(A, B)
f = Line(A, D)
E, F = Intersect(e, f)
g = OrthogonalLine(F, xAxis)
G = Intersect(b, g)
ver: y(B) / (x(D) - x(F))
differenz: k - ver
h = Segment(G, F)
q = Circle(G, C)
H, I = Intersect(q, h)
i = OrthogonalLine(I, h)
J = Intersect(c, i)
s = Circle(J, D)
K, L = Intersect(s, i)
j = OrthogonalLine(L, i)
M = Intersect(f, j)
c_1 = Circle(M, F)
N, O = Intersect(c_1, j)
l = OrthogonalLine(O, j)
Q = Intersect(l, h)
R, m, n, a_1, b_1 = Polygon(A, F, G, B)
S, e_1, f_1, g_1, h_1 = Polygon(I, G, C, J)
T, i_1, j_1, k_1, l_1 = Polygon(L, J, D, M)
U, o, m_1, n_1, p_1 = Polygon(O, M, F, Q)
q_1 = Circle(Q, I)
V, W = Intersect(q_1, l)
r_1 = OrthogonalLine(V, l)
Y = Intersect(r_1, i)
Z, s_1, v, y, t_1 = Polygon(Q, V, Y, I)
d_2 = CircleArc(F, G, A)
p = CircleArc(I, J, G)
e_2 = CircleArc(L, M, J)
f_2 = CircleArc(O, Q, M)
g_2 = CircleArc(V, Y, Q)
r = Circle(Y, L)
t = Circle(L, Y)
A_1, B_1 = Intersect(r, v)
E_1, F_1 = Intersect(t, v)
C_1, D_1 = Intersect(t, l_1)
d_1 = Segment(B_1, D_1)
c_2 = CircleArc(B_1, D_1, Y)
a_2 = Line(B, D)
b_2 = Line(G, M)
h_2 = Line(C, F)
i_2 = Line(J, A)