Quadratrix, Schritt 3
Author: Prof. Dr. Dörte Haftendorn
Date: 17.12.04

Quadratrix

Für den Steigungswinkel α gilt:

\frac{\alpha}{\frac{\pi}{2}}=\frac{z}{1}

Z = Point(yAxis)
m: tan(y(Z) pi / 2)
g(x) = m x
z = OrthogonalLine(Z, yAxis)
P = Intersect(g, z)
O = (0, 0)
A = Point(xAxis)
c = Circle(O, (1, 0))
a = OrthogonalLine(A, xAxis)
E = (1, 0)
b = OrthogonalLine(E, xAxis)
B = Intersect(g, b)
C = (2, 0)
r = Segment(O, B)
Q, e, f, h, i = Polygon((0, -r), (2, -r), C, O)
M: ((2 - r) / 2, 0)
k = Circle(M, C)
D, F = Intersect(k, yAxis)
s: -y(F)
R, d, j, l, n = Polygon(F, (-s, -s), (-s, 0), O)
G = Intersect(f, i)
H, I = Intersect(k, xAxis)
S, p, q, t = Polygon(I, F, C)
c_1 = Circle(O, B)